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Zariski's lemma : ウィキペディア英語版
Zariski's lemma
In algebra, Zariski's lemma, introduced by Oscar Zariski, states that if ''K'' is a finitely generated algebra over a field ''k'' and if ''K'' is a field, then ''K'' is a finite field extension of ''k''.
An important application of the lemma is a proof of the weak form of Hilbert's nullstellensatz: if ''I'' is a proper ideal of k(..., t_n ) (''k'' algebraically closed field), then ''I'' has a zero; i.e., there is a point ''x'' in k^n such that f(x) = 0 for all ''f'' in ''I''.〔Proof: it is enough to consider a maximal ideal \mathfrak. Let A = k(..., t_n ) and \phi: A \to A / \mathfrak be the natural surjection. By the lemma, A / \mathfrak = k and then for any f \in \mathfrak,
:f(\phi(t_1), \cdots, \phi(t_n)) = \phi(f(t_1, \cdots, t_n)) = 0;
that is to say, x = (\phi(t_1), \cdots, \phi(t_n)) is a zero of \mathfrak.〕
The lemma may also be understood from the following perspective. In general, a ring ''R'' is a Jacobson ring if and only if every finitely generated ''R''-algebra that is a field is finite over ''R''. Thus, the lemma follows from the fact that a field is a Jacobson ring.
== Proof ==
Two direct proofs, one of which is due to Zariski, are given in Atiyah–MacDonald. The lemma is also a consequence of the Noether normalization lemma. Indeed, by the normalization lemma, ''K'' is a finite module over the polynomial ring k(\ldots , x_d ) where x_1, \ldots , x_d are algebraically independent over ''k''. But since ''K'' has Krull dimension zero, the polynomial ring must have dimension zero; i.e., d=0. For Zariski's original proof, see the original paper.〔http://projecteuclid.org/download/pdf_1/euclid.bams/1183510605〕
In fact, the lemma is a special case of the general formula \dim A = \operatorname_k A for a finitely generated ''k''-algebra ''A'' that is an integral domain, which is also a consequence of the normalization lemma.

抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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